What is the solution for (dy)/(dx)=ky^2ln(x) ?

The solution for (dy)/(dx)=ky^2ln(x) is y=-1/(kxln(x)-kx+c_{1)}

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(dy)/(dx)=ky^2ln(x)

\frac{d y}{d x} = k y^{2} ln (x)

y = - \frac{1}{k x ln ( x ) - k x + c _{1}}

Solution steps

\frac{d y}{d x} = k y (x)^{2} ln (x)

Solve separable ODE:

y = - \frac{1}{k x ln ( x ) - k x + c _{1}}

y = - \frac{1}{k x ln ( x ) - k x + c _{1}}

x \to 0 lim (1 - \frac{2}{3 x})

x \to π lim (\frac{cos ( x ) - 1}{x})

\frac{d}{d x} (x (x - 9)^{2})

\int (4 x + x) d x

y = x, at x = \frac{1}{4}

What is the solution for (dy)/(dx)=ky^2ln(x) ?
The solution for (dy)/(dx)=ky^2ln(x) is y=-1/(kxln(x)-kx+c_{1)}