What is the derivative of F(X)=X-ln(1+X) ?

The derivative of F(X)=X-ln(1+X) is 1-1/(1+X)

What is the first derivative of F(X)=X-ln(1+X) ?

The first derivative of F(X)=X-ln(1+X) is 1-1/(1+X)

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derivative of

F (X) = X - ln (1 + X)

1 - \frac{1}{1 + X}

Solution steps

\frac{d}{d X} (X - ln (1 + X))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d X}{d X} - \frac{d}{d X} (ln (1 + X))

\frac{d X}{d X} = 1

\frac{d}{d X} (ln (1 + X)) = \frac{1}{1 + X}

= 1 - \frac{1}{1 + X}

\int \frac{66 x ^{2}}{x ^{4} - 65 x ^{2} + 784} d x

\frac{\partial}{\partial x} (y sin (x y) - 2 x y)

\frac{d}{d x} (x^{2} - 25 I n (x^{2}))

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What is the derivative of F(X)=X-ln(1+X) ?
The derivative of F(X)=X-ln(1+X) is 1-1/(1+X)
What is the first derivative of F(X)=X-ln(1+X) ?
The first derivative of F(X)=X-ln(1+X) is 1-1/(1+X)