What is the integral from 0 to 1 of sin(x) ?

The integral from 0 to 1 of sin(x) is -cos(1)+1

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integral from 0 to 1 of sin(x)

\int_{0}^{1} sin (x) d x

- cos (1) + 1

Decimal

0.45969 \dots

Solution steps

\int_{0}^{1} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{1}

Compute the boundaries:

- cos (1) + 1

= - cos (1) + 1

x \to 0 lim (\frac{2 x ^{2}}{sin ^{2} ( 8 x )})

f (x) = x^{4} - 2 x^{3} - 5 x - 3, at x = 1

\frac{1}{16 x ^{2}}, x, \frac{x}{10}

\int (3 x - 1) (x + 5) d x

f (x) = (3 + x^{5})^{3} - (2 + x^{3})^{4}

What is the integral from 0 to 1 of sin(x) ?
The integral from 0 to 1 of sin(x) is -cos(1)+1