What is the tangent of f(x)=7x-x^2,(1,6) ?

The tangent of f(x)=7x-x^2,(1,6) is y=5x+1

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tangent of f(x)=7x-x^2,(1,6)

tangent of

f (x) = 7 x - x^{2}, (1, 6)

y = 5 x + 1

Solution steps

Find the slope of

f (x) = 7 x - x^{2} : \frac{df ( x )}{d x} = 7 - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 6) : y = 5 x + 1

y = 5 x + 1

\int_{- 1}^{1} \frac{1}{x} d x

y = \frac{x ^{2} + 5}{6 x - x ^{2}}, (1, 5)

\int - 7 lo g_{2} (x) d x

\int e^{x} (x + 1)^{2} d x

y = x^{2} - 4 x, y = 0

What is the tangent of f(x)=7x-x^2,(1,6) ?
The tangent of f(x)=7x-x^2,(1,6) is y=5x+1