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Popular >

area y=x^2-4x,y=0

Solution

area

y = x^{2} - 4 x, y = 0

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x^{2} - 4 x d x

Solve

\int_{0}^{4} x^{2} - 4 x d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

derivative of 23x^3+x^2-12x+17 derivative of

23 x^{3} + x^{2} - 12 x + 17

(dy)/(dx)=(x-3)/(2-y)

\frac{d y}{d x} = \frac{x - 3}{2 - y}

f (x) = x \cdot ln (x)

y^{''}+16y^'+65y=6e^{-8t}cos(t)

y^{^{''}} + 16 y^{^{'}} + 65 y = 6 e^{- 8 t} cos (t)

derivative of (2-3x)^2 derivative of

(2 - 3 x)^{2}

Frequently Asked Questions (FAQ)

What is area y=x^2-4x,y=0 ?
The answer to area y=x^2-4x,y=0 is 32/3