What is the derivative of 1/(2x+3) ?

The derivative of 1/(2x+3) is -2/((2x+3)^2)

What is the first derivative of 1/(2x+3) ?

The first derivative of 1/(2x+3) is -2/((2x+3)^2)

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derivative of

\frac{1}{2 x + 3}

- \frac{2}{( 2 x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 3 ) ^{2}} \frac{d}{d x} (2 x + 3)

= - \frac{1}{( 2 x + 3 ) ^{2}} \frac{d}{d x} (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

= - \frac{1}{( 2 x + 3 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x + 3 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x + 3 ) ^{2}}

= - \frac{2}{( 2 x + 3 ) ^{2}}

x \to - 3 lim (x - 2)

\int_{1}^{2} \frac{1}{( x - 1 ) ^{2}} d x

y = 8 + 4 x^{2} - 2 x^{3}

6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

3 + x

What is the derivative of 1/(2x+3) ?
The derivative of 1/(2x+3) is -2/((2x+3)^2)
What is the first derivative of 1/(2x+3) ?
The first derivative of 1/(2x+3) is -2/((2x+3)^2)