What is laplacetransform 2t-8/3 ?

The answer to laplacetransform 2t-8/3 is 2/(s^2)-8/(3s)

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laplacetransform 2t-8/3

laplace transform

2 t - \frac{8}{3}

\frac{2}{s ^{2}} - \frac{8}{3 s}

Solution steps

L {2 t - \frac{8}{3}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 2 L {t} - L {\frac{8}{3}}

L {t} : \frac{1}{s ^{2}}

L {\frac{8}{3}} : \frac{8}{3 s}

= 2 \cdot \frac{1}{s ^{2}} - \frac{8}{3 s}

Refine

2 \frac{1}{s ^{2}} - \frac{8}{3 s} : \frac{2}{s ^{2}} - \frac{8}{3 s}

= \frac{2}{s ^{2}} - \frac{8}{3 s}

z \to 0 lim (\frac{I m ( z )}{z})

\frac{2}{x}, 4

y = 4 x^{2}, y = 6 x^{2}, 5 x + y = 6 \geq 0

\int e^{3 x + 8} d x

What is laplacetransform 2t-8/3 ?
The answer to laplacetransform 2t-8/3 is 2/(s^2)-8/(3s)