What is the solution for f^{''}(x)=-2+36x-12x^2 ?

The solution for f^{''}(x)=-2+36x-12x^2 is f(x)=-x^2+6x^3-x^4+c_{1}x+c_{2}

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f^{''}(x)=-2+36x-12x^2

f^{^{''}} (x) = - 2 + 36 x - 12 x^{2}

f (x) = - x^{2} + 6 x^{3} - x^{4} + c_{1} x + c_{2}

Solution steps

f^{''} (x) = - 2 + 36 x - 12 x^{2}

Solve

f^{''} (x) = - 2 + 36 x - 12 x^{2} : f^{'} (x) = - 2 x + 18 x^{2} - 4 x^{3} + c_{1}

Solve

f^{'} (x) = - 2 x + 18 x^{2} - 4 x^{3} + c_{1} : f (x) = - x^{2} + 6 x^{3} - x^{4} + c_{1} x + c_{2}

f (x) = - x^{2} + 6 x^{3} - x^{4} + c_{1} x + c_{2}

- 4 sin (2 x)

f (x) = arccos (e^{- x})

x \to \frac{1}{2} lim (8 x^{3} - 1)

x \to 2 lim (\frac{x ^{2} - 4}{x - 4})

\frac{1}{5 - 7 x}

What is the solution for f^{''}(x)=-2+36x-12x^2 ?
The solution for f^{''}(x)=-2+36x-12x^2 is f(x)=-x^2+6x^3-x^4+c_{1}x+c_{2}