What is the solution for (dy}{dx}=-\frac{(e^x))/8 ?

The solution for (dy}{dx}=-\frac{(e^x))/8 is y=-1/8 e^x+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=-\frac{(e^x))/8

\frac{d y}{d x} = - \frac{( e ^{x} )}{8}

y = - \frac{1}{8} e^{x} + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{( e ^{x} )}{8}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = - \frac{( e ^{x} )}{8}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - \frac{e ^{x}}{8} d x

\int - \frac{e ^{x}}{8} d x = - \frac{1}{8} e^{x} + c_{1}

y = - \frac{1}{8} e^{x} + c_{1}

\int - 2 e^{2 t} d t

\int \frac{1}{1 + 17 x} d x

\int (x sin (x)) d x

y = \frac{2 x}{4 + x ^{2}}

\frac{d x}{d t} = \frac{2}{x}

What is the solution for (dy}{dx}=-\frac{(e^x))/8 ?
The solution for (dy}{dx}=-\frac{(e^x))/8 is y=-1/8 e^x+c_{1}