What is the integral from 27 to-1 of (-8\sqrt[3]{x}) ?

The integral from 27 to-1 of (-8\sqrt[3]{x}) is 480

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integral from 27 to-1 of (-8\sqrt[3]{x})

480

Solution steps

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{27}

= - (- 8 [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{27})

Simplify

= 8 [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{27}

Compute the boundaries:

60

= 8 \cdot 60

Simplify

= 480

y^{^{'}} = 3 y + 5

\int - 10 sin (x) d x

x = y^{2} - 8, x = 2 y

\frac{d}{d x} (\frac{x - 3}{x} + ln (\frac{x}{3}))

What is the integral from 27 to-1 of (-8\sqrt[3]{x}) ?
The integral from 27 to-1 of (-8\sqrt[3]{x}) is 480