What is the derivative of y=(2x^4+1)^2 ?

The derivative of y=(2x^4+1)^2 is 16x^3(2x^4+1)

What is the first derivative of y=(2x^4+1)^2 ?

The first derivative of y=(2x^4+1)^2 is 16x^3(2x^4+1)

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derivative of

y = (2 x^{4} + 1)^{2}

16 x^{3} (2 x^{4} + 1)

Solution steps

\frac{d}{d x} ((2 x^{4} + 1)^{2})

Apply the chain rule:

2 (2 x^{4} + 1) \frac{d}{d x} (2 x^{4} + 1)

= 2 (2 x^{4} + 1) \frac{d}{d x} (2 x^{4} + 1)

\frac{d}{d x} (2 x^{4} + 1) = 8 x^{3}

= 2 (2 x^{4} + 1) \cdot 8 x^{3}

Simplify

= 16 x^{3} (2 x^{4} + 1)

f (x) = \frac{4 x}{x ^{2} + 1}, (0, 0)

\int_{1}^{3} \frac{1}{( x - 1 ) ^{\frac{3}{2}}} d x

\int \frac{1}{2 sin ( x ) + cos ( x )} d x

y^{^{'}} = 2 y + x e^{x}

x \to + 0 lim (\frac{ln ( x )}{x})

What is the derivative of y=(2x^4+1)^2 ?
The derivative of y=(2x^4+1)^2 is 16x^3(2x^4+1)
What is the first derivative of y=(2x^4+1)^2 ?
The first derivative of y=(2x^4+1)^2 is 16x^3(2x^4+1)