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Popular >

derivative of-4sin(2x+3cos(3x))

Solution

\frac{d}{d x} (- 4 sin (2 x) + 3 cos (3 x))

Solution

- 8 cos (2 x) - 9 sin (3 x)

Solution steps

\frac{d}{d x} (- 4 sin (2 x) + 3 cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 sin (2 x)) + \frac{d}{d x} (3 cos (3 x))

\frac{d}{d x} (4 sin (2 x)) = 8 cos (2 x)

\frac{d}{d x} (3 cos (3 x)) = - 9 sin (3 x)

= - 8 cos (2 x) - 9 sin (3 x)

Popular Examples

integral from 0 to 1 of 6e^{-4x}

\int_{0}^{1} 6 e^{- 4 x} d x

(dy)/(dx)+(2xy)/(1+x^2)=-2xy^2

\frac{d y}{d x} + \frac{2 x y}{1 + x ^{2}} = - 2 x y^{2}

inverse oflaplace (28s)/((s^2+11))inverse laplace

\frac{28 s}{( s ^{2} + 11 )}

(dy)/(dx)+4tan(4x)(y)=3cos(4x)

\frac{d y}{d x} + 4 tan (4 x) (y) = 3 cos (4 x)

integral from-2 to 3 of (x^2+3x-13)

\int_{- 2}^{3} (x^{2} + 3 x - 13) d x

Frequently Asked Questions (FAQ)

What is the derivative of-4sin(2x+3cos(3x)) ?
The derivative of-4sin(2x+3cos(3x)) is -8cos(2x)-9sin(3x)
What is the first derivative of-4sin(2x+3cos(3x)) ?
The first derivative of-4sin(2x+3cos(3x)) is -8cos(2x)-9sin(3x)