What is the derivative of 2x^{3/2}+7 ?

The derivative of 2x^{3/2}+7 is 3x^{1/2}

What is the first derivative of 2x^{3/2}+7 ?

The first derivative of 2x^{3/2}+7 is 3x^{1/2}

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\frac{d}{d x} (2 x^{\frac{3}{2}} + 7)

3 x^{\frac{1}{2}}

Solution steps

\frac{d}{d x} (2 x^{\frac{3}{2}} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{\frac{3}{2}}) + \frac{d}{d x} (7)

\frac{d}{d x} (2 x^{\frac{3}{2}}) = 3 x^{\frac{1}{2}}

\frac{d}{d x} (7) = 0

= 3 x^{\frac{1}{2}} + 0

Simplify

= 3 x^{\frac{1}{2}}

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What is the derivative of 2x^{3/2}+7 ?
The derivative of 2x^{3/2}+7 is 3x^{1/2}
What is the first derivative of 2x^{3/2}+7 ?
The first derivative of 2x^{3/2}+7 is 3x^{1/2}