What is the integral of 5/(\sqrt[3]{x^2)} ?

The integral of 5/(\sqrt[3]{x^2)} is 15\sqrt[3]{x}+C

Popular >

integral of 5/(\sqrt[3]{x^2)}

\int \frac{5}{3 x ^{2}} d x

15 3 x + C

Solution steps

\int \frac{5}{3 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{3 x ^{2}} d x

3 x^{2} = x^{\frac{2}{3}},

assuming

x \geq 0

= 5 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 5 \cdot 3 x^{\frac{1}{3}}

Simplify

5 \cdot 3 x^{\frac{1}{3}} : 15 3 x

= 15 3 x

Add a constant to the solution

= 15 3 x + C

\int \frac{4}{( x + 1 ) ( x + 3 )} d x

x \to \infty lim (\frac{8 ^{x}}{9 ^{x + 1}})

\int \frac{32}{1 - cos ( 4 x )} d x

\int_{0}^{4} \frac{x}{x ^{2} - 4} d x

\frac{\partial}{\partial x} (r (θ, x) cos (θ))

What is the integral of 5/(\sqrt[3]{x^2)} ?
The integral of 5/(\sqrt[3]{x^2)} is 15\sqrt[3]{x}+C