What is the derivative of 3(1-x^{-2}) ?

The derivative of 3(1-x^{-2}) is 6/((1-x)^3)

What is the first derivative of 3(1-x^{-2}) ?

The first derivative of 3(1-x^{-2}) is 6/((1-x)^3)

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\frac{d}{d x} (3 (1 - x)^{- 2})

\frac{6}{( 1 - x ) ^{3}}

Solution steps

\frac{d}{d x} (3 (1 - x)^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((1 - x)^{- 2})

Apply the chain rule:

- \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

= - \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 3 (- \frac{2}{( 1 - x ) ^{3}} (- 1))

Simplify

3 (- \frac{2}{( 1 - x ) ^{3}} (- 1)) : \frac{6}{( 1 - x ) ^{3}}

= \frac{6}{( 1 - x ) ^{3}}

y^{^{'}} = \frac{sin ( x )}{y}

\frac{d}{d x} (\frac{x ^{3}}{4} - 4 x)

\int x sin (- 4 x) d x

\int \frac{1}{( x ^{2} + 25 ) ^{\frac{3}{2}}} d x

(4 x - y) d x + (6 y - x) d y = 0

What is the derivative of 3(1-x^{-2}) ?
The derivative of 3(1-x^{-2}) is 6/((1-x)^3)
What is the first derivative of 3(1-x^{-2}) ?
The first derivative of 3(1-x^{-2}) is 6/((1-x)^3)