What is laplacetransform 3t+1 ?

The answer to laplacetransform 3t+1 is 3/(s^2)+1/s

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laplacetransform 3t+1

laplace transform

3 t + 1

\frac{3}{s ^{2}} + \frac{1}{s}

Solution steps

L {3 t + 1}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 3 L {t} + L {1}

L {t} : \frac{1}{s ^{2}}

L {1} : \frac{1}{s}

= 3 \cdot \frac{1}{s ^{2}} + \frac{1}{s}

Refine

3 \frac{1}{s ^{2}} + \frac{1}{s} : \frac{3}{s ^{2}} + \frac{1}{s}

= \frac{3}{s ^{2}} + \frac{1}{s}

(sin (4 x))^{^{'}}

\int_{0}^{b} \frac{1}{9 - x ^{2}} d x

\int - 9.8 x d x

(4 t + 2 y + 5) d t - d y = 0

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 3} d x

What is laplacetransform 3t+1 ?
The answer to laplacetransform 3t+1 is 3/(s^2)+1/s