What is the derivative of ln(9-2x) ?

The derivative of ln(9-2x) is -2/(9-2x)

What is the first derivative of ln(9-2x) ?

The first derivative of ln(9-2x) is -2/(9-2x)

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derivative of

ln (9 - 2 x)

- \frac{2}{9 - 2 x}

Solution steps

\frac{d}{d x} (ln (9 - 2 x))

Apply the chain rule:

\frac{1}{9 - 2 x} \frac{d}{d x} (9 - 2 x)

= \frac{1}{9 - 2 x} \frac{d}{d x} (9 - 2 x)

\frac{d}{d x} (9 - 2 x) = - 2

= \frac{1}{9 - 2 x} (- 2)

Simplify

\frac{1}{9 - 2 x} (- 2) : - \frac{2}{9 - 2 x}

= - \frac{2}{9 - 2 x}

\frac{d}{d x} (\frac{1}{3 x + 5})

\int_{1}^{2} x d x

\frac{d}{d x} ([x + (x + sin^{2} (x))^{7}]^{4})

\frac{\partial}{\partial x} (cos^{3} (x^{3} y^{8}))

y^{^{''}} + 5 y^{^{'}} + 6 y = 4 e^{- 2 t}

What is the derivative of ln(9-2x) ?
The derivative of ln(9-2x) is -2/(9-2x)
What is the first derivative of ln(9-2x) ?
The first derivative of ln(9-2x) is -2/(9-2x)