What is implicit (dy)/(dx),x+y=1 ?

The answer to implicit (dy)/(dx),x+y=1 is (dy)/(dx)=-1

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implicit (dy)/(dx),x+y=1

implicit derivative

\frac{d y}{d x}, x + y = 1

\frac{d y}{d x} = - 1

Solution steps

x + y = 1

Treat

y

y (x)

Differentiate both sides:

1 + \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - 1

\frac{d y}{d x} = - 1

x = - 2 y^{2} - 4 y + 1, x = y^{2} + 8 y + 10

\frac{\partial}{\partial x} (e^{3 x yz - 8})

(- 2, - 10), (0, - 4)

\frac{d}{d x} (\frac{4 x}{x ^{2} + 7})

\int x^{\frac{3}{2}} d x

What is implicit (dy)/(dx),x+y=1 ?
The answer to implicit (dy)/(dx),x+y=1 is (dy)/(dx)=-1