What is the limit as x approaches-1/3 of 9x(4x+9)^2 ?

The limit as x approaches-1/3 of 9x(4x+9)^2 is -529/3

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limit as x approaches-1/3 of 9x(4x+9)^2

x \to - \frac{1}{3} lim (9 x (4 x + 9)^{2})

- \frac{529}{3}

Decimal

- 176.33333 \dots

Solution steps

x \to - \frac{1}{3} lim (9 x (4 x + 9)^{2})

Plug in the value

x = - \frac{1}{3}

= 9 (- \frac{1}{3}) (4 (- \frac{1}{3}) + 9)^{2}

Simplify

9 (- \frac{1}{3}) (4 (- \frac{1}{3}) + 9)^{2} : - \frac{529}{3}

= - \frac{529}{3}

\int (\frac{9}{x}) d x

arccsc (- 9 t^{2})

\int \frac{x + 7}{x ^{2} + 9} d x

\int \frac{1}{v ^{2}} d v

\frac{d}{d x} (sec^{n} (x))

What is the limit as x approaches-1/3 of 9x(4x+9)^2 ?
The limit as x approaches-1/3 of 9x(4x+9)^2 is -529/3