What is integral from 0 to 1 of integral from 2x to 2 of (x-y) ?

The answer to integral from 0 to 1 of integral from 2x to 2 of (x-y) is -1

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integral from 0 to 1 of integral from 2x to 2 of (x-y)

\int_{0}^{1} \int_{2 x}^{2} (x - y) d y d x

- 1

Solution steps

\int_{0}^{1} \int_{2 x}^{2} x - y d y d x

\int_{2 x}^{2} x - y d y = 2 x - 2

= \int_{0}^{1} 2 x - 2 d x

\int_{0}^{1} 2 x - 2 d x = - 1

= - 1

\frac{sin ( x )}{4 x}

\int 0.4 x d x

\frac{d}{d x} ((x + (x^{2} - 4)^{3})^{10})

x \to 0 + lim (\frac{x}{- 4 x ^{3} - 8 x})

\frac{\partial}{\partial x} ((x + y) e^{x + 2 y})

What is integral from 0 to 1 of integral from 2x to 2 of (x-y) ?
The answer to integral from 0 to 1 of integral from 2x to 2 of (x-y) is -1