What is the derivative of (sin(x))/(4x) ?

The derivative of (sin(x))/(4x) is (xcos(x)-sin(x))/(4x^2)

What is the first derivative of (sin(x))/(4x) ?

The first derivative of (sin(x))/(4x) is (xcos(x)-sin(x))/(4x^2)

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derivative of

\frac{sin ( x )}{4 x}

\frac{x cos ( x ) - sin ( x )}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{sin ( x )}{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (\frac{sin ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{4} \cdot \frac{\frac{d}{d x} ( sin ( x ) ) x - \frac{d x}{d x} sin ( x )}{x ^{2}}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d x}{d x} = 1

= \frac{1}{4} \cdot \frac{cos ( x ) x - 1 \cdot sin ( x )}{x ^{2}}

Simplify

\frac{1}{4} \cdot \frac{cos ( x ) x - 1 \cdot sin ( x )}{x ^{2}} : \frac{x cos ( x ) - sin ( x )}{4 x ^{2}}

= \frac{x cos ( x ) - sin ( x )}{4 x ^{2}}

\int 0.4 x d x

\frac{d}{d x} ((x + (x^{2} - 4)^{3})^{10})

x \to 0 + lim (\frac{x}{- 4 x ^{3} - 8 x})

\frac{\partial}{\partial x} ((x + y) e^{x + 2 y})

\int \frac{x ^{2} + 2}{x ^{2} - x} d x

What is the derivative of (sin(x))/(4x) ?
The derivative of (sin(x))/(4x) is (xcos(x)-sin(x))/(4x^2)
What is the first derivative of (sin(x))/(4x) ?
The first derivative of (sin(x))/(4x) is (xcos(x)-sin(x))/(4x^2)