What is the integral of (x^2+2)/(x^2-x) ?

The integral of (x^2+2)/(x^2-x) is x+3ln|x-1|-2ln|x|-1+C

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integral of (x^2+2)/(x^2-x)

\int \frac{x ^{2} + 2}{x ^{2} - x} d x

x + 3 ln ∣ x - 1 ∣ - 2 ln ∣ x ∣ - 1 + C

Solution steps

\int \frac{x ^{2} + 2}{x ^{2} - x} d x

Expand

\frac{x ^{2} + 2}{x ^{2} - x} : \frac{x ^{2}}{x ^{2} - x} + \frac{2}{x ^{2} - x}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{x ^{2} - x} d x + \int \frac{2}{x ^{2} - x} d x

\int \frac{x ^{2}}{x ^{2} - x} d x = x - 1 + ln ∣ x - 1 ∣

\int \frac{2}{x ^{2} - x} d x = 2 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

= x - 1 + ln ∣ x - 1 ∣ + 2 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

Simplify

x - 1 + ln ∣ x - 1 ∣ + 2 (- ln ∣ x ∣ + ln ∣ x - 1 ∣) : x + 3 ln ∣ x - 1 ∣ - 2 ln ∣ x ∣ - 1

= x + 3 ln ∣ x - 1 ∣ - 2 ln ∣ x ∣ - 1

Add a constant to the solution

= x + 3 ln ∣ x - 1 ∣ - 2 ln ∣ x ∣ - 1 + C

\int \frac{( cos ( x ) + sin ( 2 x ) )}{sin ( x )} d x

\int 5 x + 4 y d x

\frac{( x - 6 )}{x + 6}

\frac{d}{d x} ((ln (x + 4))^{2})

f (t) = 4 e^{t}

What is the integral of (x^2+2)/(x^2-x) ?
The integral of (x^2+2)/(x^2-x) is x+3ln|x-1|-2ln|x|-1+C