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Popular >

derivative of 6sin^2(2xcos(2x)+2x)

Solution

\frac{d}{d x} (6 sin^{2} (2 x) cos (2 x) + 2 x)

Solution

6 (2 sin (4 x) cos (2 x) - 2 sin^{3} (2 x)) + 2

Solution steps

\frac{d}{d x} (6 sin^{2} (2 x) cos (2 x) + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 sin^{2} (2 x) cos (2 x)) + \frac{d}{d x} (2 x)

\frac{d}{d x} (6 sin^{2} (2 x) cos (2 x)) = 6 (2 sin (4 x) cos (2 x) - 2 sin^{3} (2 x))

\frac{d}{d x} (2 x) = 2

= 6 (2 sin (4 x) cos (2 x) - 2 sin^{3} (2 x)) + 2

Popular Examples

x^2y^{''}+xy^'-y=sqrt(x)

x^{2} y^{^{''}} + x y^{^{'}} - y = x

x^2y^'+3xy=e^{-x}

x^{2} y^{^{'}} + 3 x y = e^{- x}

integral of 2x^2

\int 2 x^{2} d x

tangent of sqrt(x)+1/(sqrt(x^3))(1.2)tangent of

x + \frac{1}{x ^{3}} (1.2)

(\partial)/(\partial y)(3x^3y^2)

\frac{\partial}{\partial y} (3 x^{3} y^{2})

Frequently Asked Questions (FAQ)

What is the derivative of 6sin^2(2xcos(2x)+2x) ?
The derivative of 6sin^2(2xcos(2x)+2x) is 6(2sin(4x)cos(2x)-2sin^3(2x))+2
What is the first derivative of 6sin^2(2xcos(2x)+2x) ?
The first derivative of 6sin^2(2xcos(2x)+2x) is 6(2sin(4x)cos(2x)-2sin^3(2x))+2