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Popular >

y^'=(x-2)e^{-2y}

Solution

y^{^{'}} = (x - 2) e^{- 2 y}

Solution

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

Solution steps

y^{'} (x) = (x - 2) e^{- 2 y}

Solve separable ODE:

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

Popular Examples

integral of 1/(9e^{-6x)+e^{6x}}

\int \frac{1}{9 e ^{- 6 x} + e ^{6 x}} d x

3 y^{^{''}} + 27 y = 0

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\frac{32}{x}

(\partial)/(\partial x)(e^x-e^{x^2})

\frac{\partial}{\partial x} (e^{x} - e^{x^{2}})

integral of tan(2x)sec(2x)

\int tan (2 x) sec (2 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x-2)e^{-2y} ?
The solution for y^'=(x-2)e^{-2y} is y=(ln(x^2-4x+c_{1}))/2