What is the derivative of e^{-x}+x-1 ?

The derivative of e^{-x}+x-1 is -e^{-x}+1

What is the first derivative of e^{-x}+x-1 ?

The first derivative of e^{-x}+x-1 is -e^{-x}+1

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\frac{d}{d x} (e^{- x} + x - 1)

- e^{- x} + 1

Solution steps

\frac{d}{d x} (e^{- x} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- x}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= - e^{- x} + 1 - 0

Simplify

= - e^{- x} + 1

x \to + 2 lim (\frac{x - 2}{x - 1})

\frac{d}{d t} (ln (cos (t)))

\frac{d}{d x} y^{4} = \frac{d}{d x} (4 x)

x, 11, \frac{1}{44} x^{2}

\int 2 \frac{y}{5} d y

What is the derivative of e^{-x}+x-1 ?
The derivative of e^{-x}+x-1 is -e^{-x}+1
What is the first derivative of e^{-x}+x-1 ?
The first derivative of e^{-x}+x-1 is -e^{-x}+1