What is the derivative of y=x^3+7x^2-4 ?

The derivative of y=x^3+7x^2-4 is 3x^2+14x

What is the first derivative of y=x^3+7x^2-4 ?

The first derivative of y=x^3+7x^2-4 is 3x^2+14x

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derivative of

y = x^{3} + 7 x^{2} - 4

3 x^{2} + 14 x

Solution steps

\frac{d}{d x} (x^{3} + 7 x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (7 x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x^{2}) = 14 x

\frac{d}{d x} (4) = 0

= 3 x^{2} + 14 x - 0

Simplify

= 3 x^{2} + 14 x

\frac{d y}{d t} = 4 t - 0.1 y t

x^{2} - 5 x + 1

- \frac{2 x ^{2}}{5 y ^{2}}

\int \frac{( x - 1 ) e ^{x}}{x ^{2}} d x

x \to \infty lim (∣ 2 - x ∣)

What is the derivative of y=x^3+7x^2-4 ?
The derivative of y=x^3+7x^2-4 is 3x^2+14x
What is the first derivative of y=x^3+7x^2-4 ?
The first derivative of y=x^3+7x^2-4 is 3x^2+14x