What is the derivative of-(2x^2)/(5y^2) ?

The derivative of-(2x^2)/(5y^2) is -(4x)/(5y^2)

What is the first derivative of-(2x^2)/(5y^2) ?

The first derivative of-(2x^2)/(5y^2) is -(4x)/(5y^2)

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derivative of

- \frac{2 x ^{2}}{5 y ^{2}}

- \frac{4 x}{5 y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{2 x ^{2}}{5 y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{2}{5 y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{2}{5 y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{2}{5 y ^{2}} \cdot 2 x^{2 - 1} : - \frac{4 x}{5 y ^{2}}

= - \frac{4 x}{5 y ^{2}}

\int \frac{( x - 1 ) e ^{x}}{x ^{2}} d x

x \to \infty lim (∣ 2 - x ∣)

\frac{\partial}{\partial x} (cos (8 y - 3 x))

\frac{d}{d x} (\frac{1}{2} (cos (5 x))^{2})

y^{^{''}} - 2 y^{^{'}} = 12 x - 10

What is the derivative of-(2x^2)/(5y^2) ?
The derivative of-(2x^2)/(5y^2) is -(4x)/(5y^2)
What is the first derivative of-(2x^2)/(5y^2) ?
The first derivative of-(2x^2)/(5y^2) is -(4x)/(5y^2)