What is the solution for y^{''}-2y^'=12x-10 ?

The solution for y^{''}-2y^'=12x-10 is y=c_{1}e^{2x}+c_{2}-3x^2+2x

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y^{''}-2y^'=12x-10

y^{^{''}} - 2 y^{^{'}} = 12 x - 10

y = c_{1} e^{2 x} + c_{2} - 3 x^{2} + 2 x

Solution steps

y^{''} (x) - 2 y^{'} (x) = 12 x - 10

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} - 3 x^{2} + 2 x

y = c_{1} e^{2 x} + c_{2} - 3 x^{2} + 2 x

3 x^{2} + 2 x

x^{2} - 4, 5

\int_{1}^{2} x^{3} + \frac{1}{4 x ^{3}} d x

x \to \infty lim (- 7)

cos (x) - tan (x)

What is the solution for y^{''}-2y^'=12x-10 ?
The solution for y^{''}-2y^'=12x-10 is y=c_{1}e^{2x}+c_{2}-3x^2+2x