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Popular >

xy^'+4y=x^3-x

Solution

x y^{^{'}} + 4 y = x^{3} - x

Solution

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

Solution steps

x y^{'} (x) + 4 y = x^{3} - x

Solve linear ODE:

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

Popular Examples

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integral from 1 to e of ln(9x)

\int_{1}^{e} ln (9 x) d x

(\partial)/(\partial x)(x^5e^{xy}+3x)

\frac{\partial}{\partial x} (x^{5} e^{x y} + 3 x)

Frequently Asked Questions (FAQ)

What is the solution for xy^'+4y=x^3-x ?
The solution for xy^'+4y=x^3-x is y=(x^3)/7-x/5+(c_{1})/(x^4)