What is the derivative of (14x+6x^2/((7+6x)^2)) ?

The derivative of (14x+6x^2/((7+6x)^2)) is (98)/((7+6x)^3)

What is the first derivative of (14x+6x^2/((7+6x)^2)) ?

The first derivative of (14x+6x^2/((7+6x)^2)) is (98)/((7+6x)^3)

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\frac{d}{d x} (\frac{14 x + 6 x ^{2}}{( 7 + 6 x ) ^{2}})

\frac{98}{( 7 + 6 x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{14 x + 6 x ^{2}}{( 7 + 6 x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 14 x + 6 x ^{2} ) ( 7 + 6 x ) ^{2} - \frac{d}{d x} ( ( 7 + 6 x ) ^{2} ) ( 14 x + 6 x ^{2} )}{( ( 7 + 6 x ) ^{2} ) ^{2}}

\frac{d}{d x} (14 x + 6 x^{2}) = 14 + 12 x

\frac{d}{d x} ((7 + 6 x)^{2}) = 12 (7 + 6 x)

= \frac{( 14 + 12 x ) ( 7 + 6 x ) ^{2} - 12 ( 7 + 6 x ) ( 14 x + 6 x ^{2} )}{( ( 7 + 6 x ) ^{2} ) ^{2}}

Simplify

\frac{( 14 + 12 x ) ( 7 + 6 x ) ^{2} - 12 ( 7 + 6 x ) ( 14 x + 6 x ^{2} )}{( ( 7 + 6 x ) ^{2} ) ^{2}} : \frac{98}{( 7 + 6 x ) ^{3}}

= \frac{98}{( 7 + 6 x ) ^{3}}

\frac{\partial}{\partial x} (\frac{- x - 7 y}{y ^{2} + 6 x ^{2}})

\frac{d}{d x} ((3 x + 2 y)^{5})

\int_{0}^{4} \frac{5}{2 x + 1} d x

3^{t}

x \cdot cos (2 x)

What is the derivative of (14x+6x^2/((7+6x)^2)) ?
The derivative of (14x+6x^2/((7+6x)^2)) is (98)/((7+6x)^3)
What is the first derivative of (14x+6x^2/((7+6x)^2)) ?
The first derivative of (14x+6x^2/((7+6x)^2)) is (98)/((7+6x)^3)