What is (\partial)/(\partial x)(7e^{-4x}) ?

The answer to (\partial)/(\partial x)(7e^{-4x}) is -28e^{-4x}

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(\partial)/(\partial x)(7e^{-4x})

\frac{\partial}{\partial x} (7 e^{- 4 x})

- 28 e^{- 4 x}

Solution steps

\frac{\partial}{\partial x} (7 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{\partial}{\partial x} (- 4 x)

= e^{- 4 x} \frac{\partial}{\partial x} (- 4 x)

\frac{\partial}{\partial x} (- 4 x) = - 4

= 7 e^{- 4 x} (- 4)

Simplify

= - 28 e^{- 4 x}

\int_{2}^{6} f (x) d x

(2, 3), (4, 8)

y^{^{''}} + 9 y = 0, y (0) = 8, y^{^{'}} (0) = 7

\frac{\frac{1}{500}}{140 + 8 s + s ^{2}}

\int (2 x - \frac{1}{2 x}) d x

What is (\partial)/(\partial x)(7e^{-4x}) ?
The answer to (\partial)/(\partial x)(7e^{-4x}) is -28e^{-4x}