What is (\partial)/(\partial x)(ln(x+ct)) ?

The answer to (\partial)/(\partial x)(ln(x+ct)) is 1/(x+ct)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ln(x+ct))

\frac{\partial}{\partial x} (ln (x + c t))

\frac{1}{x + c t}

Solution steps

\frac{\partial}{\partial x} (ln (x + c t))

Treat

c, t

as a constant

Apply the chain rule:

\frac{1}{x + c t} \frac{\partial}{\partial x} (x + c t)

= \frac{1}{x + c t} \frac{\partial}{\partial x} (x + c t)

\frac{\partial}{\partial x} (x + c t) = 1

= \frac{1}{x + c t} \cdot 1

Simplify

= \frac{1}{x + c t}

(1 + \frac{2}{x})^{x}

\int \frac{3}{x ^{2} + 4} d x

- sin (2 t)

y = arctan (4 t)

x \to 2 - lim (2 - x^{2})

What is (\partial)/(\partial x)(ln(x+ct)) ?
The answer to (\partial)/(\partial x)(ln(x+ct)) is 1/(x+ct)