What is area y=e^x,y=x,x=0,x=2 ?

The answer to area y=e^x,y=x,x=0,x=2 is e^2-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=x,x=0,x=2

area

y = e^{x}, y = x, x = 0, x = 2

e^{2} - 3

Decimal

4.38905 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} ∣ e^{x} - x ∣ d x

Solve

\int_{0}^{2} ∣ e^{x} - x ∣ d x : e^{2} - 3

The area is:

= e^{2} - 3

\int \frac{6 x ^{2} + 13 x + 6}{( x + 2 ) ( x + 1 ) ^{2}} d x

y = e^{x^{3}}, (- 1, \frac{1}{e})

\frac{( y - 2 ) ^{3}}{( y ^{2} + 4 y ) ^{7}}

x \to + 3 lim (f (x))

x \to 90 lim (sin (x))