tangent y=(2x)/(x^2-7),(3,3)

解答

切线

y = \frac{2 x}{x ^{2} - 7}, (3, 3)

y = - 8 x + 27

求解步骤

计算

y = \frac{2 x}{x ^{2} - 7}

的斜率:

\frac{d y}{d x} = \frac{2 ( - x ^{2} - 7 )}{( x ^{2} - 7 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

找到斜率 m=

- 8

且穿过

(3, 3)

的直线:

y = - 8 x + 27

y = - 8 x + 27

a re a x, 2 x 1 - x^{2}

x \to 2 lim (x (x - 1) (x + 1))

n = 0 \sum \infty 6^{n}

\int \frac{x ^{3} - 1}{x ^{2}} d x

\frac{d}{d x} (\frac{15}{ln ( x )})