What is the tangent of y=(2x)/(x^2-7),(3,3) ?

The tangent of y=(2x)/(x^2-7),(3,3) is y=-8x+27

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tangent of y=(2x)/(x^2-7),(3,3)

tangent of

y = \frac{2 x}{x ^{2} - 7}, (3, 3)

y = - 8 x + 27

Solution steps

Find the slope of

y = \frac{2 x}{x ^{2} - 7} : \frac{d y}{d x} = \frac{2 ( - x ^{2} - 7 )}{( x ^{2} - 7 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(3, 3) : y = - 8 x + 27

y = - 8 x + 27

x, 2 x 1 - x^{2}

x \to 2 lim (x (x - 1) (x + 1))

n = 0 \sum \infty 6^{n}

\int \frac{x ^{3} - 1}{x ^{2}} d x

\frac{d}{d x} (\frac{15}{ln ( x )})

What is the tangent of y=(2x)/(x^2-7),(3,3) ?
The tangent of y=(2x)/(x^2-7),(3,3) is y=-8x+27