What is (d^2)/(dx^2)(-2x^4-2x^3+60x^2-22) ?

The answer to (d^2)/(dx^2)(-2x^4-2x^3+60x^2-22) is -24x^2-12x+120

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2)/(dx^2)(-2x^4-2x^3+60x^2-22)

\frac{d ^{2}}{d x ^{2}} (- 2 x^{4} - 2 x^{3} + 60 x^{2} - 22)

- 24 x^{2} - 12 x + 120

Solution steps

\frac{d ^{2}}{d x ^{2}} (- 2 x^{4} - 2 x^{3} + 60 x^{2} - 22)

\frac{d}{d x} (- 2 x^{4} - 2 x^{3} + 60 x^{2} - 22) = - 8 x^{3} - 6 x^{2} + 120 x

= \frac{d}{d x} (- 8 x^{3} - 6 x^{2} + 120 x)

\frac{d}{d x} (- 8 x^{3} - 6 x^{2} + 120 x) = - 24 x^{2} - 12 x + 120

= - 24 x^{2} - 12 x + 120

\frac{d}{d x} (2 x cos (x) - 2 sin (x))

\frac{x}{1 + x ^{2}}, at x = 2

\int 0.02 e^{x} d x

2 x y^{2} + 4 = 2 (3 - x^{2} y) y^{^{'}}, y (- 1) = 8

\frac{d}{d x} (x^{3} + 3 x^{2} - 144 x)

What is (d^2)/(dx^2)(-2x^4-2x^3+60x^2-22) ?
The answer to (d^2)/(dx^2)(-2x^4-2x^3+60x^2-22) is -24x^2-12x+120