What is the derivative of sqrt(25-x^2-y^2) ?

The derivative of sqrt(25-x^2-y^2) is -(x+y\frac{dy)/(dx)}{sqrt(-x^2-y^2+25)}

What is the first derivative of sqrt(25-x^2-y^2) ?

The first derivative of sqrt(25-x^2-y^2) is -(x+y\frac{dy)/(dx)}{sqrt(-x^2-y^2+25)}

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\frac{d}{d x} (25 - x^{2} - y^{2})

- \frac{x + y \frac{d y}{d x}}{- x ^{2} - y ^{2} + 25}

Solution steps

\frac{d}{d x} (25 - x^{2} - y^{2})

Apply the chain rule:

\frac{1}{2 25 - x ^{2} - y ^{2}} \frac{d}{d x} (25 - x^{2} - y^{2})

= \frac{1}{2 25 - x ^{2} - y ^{2}} \frac{d}{d x} (25 - x^{2} - y^{2})

\frac{d}{d x} (25 - x^{2} - y^{2}) = - 2 x - 2 y \frac{d y}{d x}

= \frac{1}{2 25 - x ^{2} - y ^{2}} (- 2 x - 2 y \frac{d y}{d x})

Simplify

\frac{1}{2 25 - x ^{2} - y ^{2}} (- 2 x - 2 y \frac{d y}{d x}) : - \frac{x + y \frac{d y}{d x}}{- x ^{2} - y ^{2} + 25}

= - \frac{x + y \frac{d y}{d x}}{- x ^{2} - y ^{2} + 25}

f (x) = \frac{x ^{2}}{x + 8}, (1, \frac{1}{9})

y^{^{'}} = y^{2} + 1

f (x) = x 4 - x

\frac{d}{d x} (2 x + 3 y)

x \to 2 π lim (\frac{sin ( x )}{x})

What is the derivative of sqrt(25-x^2-y^2) ?
The derivative of sqrt(25-x^2-y^2) is -(x+y\frac{dy)/(dx)}{sqrt(-x^2-y^2+25)}
What is the first derivative of sqrt(25-x^2-y^2) ?
The first derivative of sqrt(25-x^2-y^2) is -(x+y\frac{dy)/(dx)}{sqrt(-x^2-y^2+25)}