What is the solution for y^'=(ln(2))/7 y-20,y(0)=200 ?

The solution for y^'=(ln(2))/7 y-20,y(0)=200 is y=(140)/(ln(2))+2^{t/7}(200-(140)/(ln(2)))

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y^'=(ln(2))/7 y-20,y(0)=200

y^{^{'}} = \frac{ln ( 2 )}{7} y - 20, y (0) = 200

y = \frac{140}{ln ( 2 )} + 2^{\frac{t}{7}} (200 - \frac{140}{ln ( 2 )})

Solution steps

y^{'} (t) = \frac{ln ( 2 )}{7} y - 20

Solve linear ODE:

y = \frac{140}{ln ( 2 )} + 2^{\frac{t}{7}} (200 - \frac{140}{ln ( 2 )})

y = \frac{140}{ln ( 2 )} + 2^{\frac{t}{7}} (200 - \frac{140}{ln ( 2 )})

\frac{w}{w + \frac{d}{w}}

\frac{d}{d x} (4 y - 2 x)

f (x) = 3 36 x^{2} + 10

\frac{\partial}{\partial x} (- 2 x - 8 y + 18)

\frac{d}{d x} (cos (arccos (x)))

What is the solution for y^'=(ln(2))/7 y-20,y(0)=200 ?
The solution for y^'=(ln(2))/7 y-20,y(0)=200 is y=(140)/(ln(2))+2^{t/7}(200-(140)/(ln(2)))