What is the solution for (dy)/(dx)=y(1+x)^{-1} ?

The solution for (dy)/(dx)=y(1+x)^{-1} is y=e^{c_{1}}+e^{c_{1}}x

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(dy)/(dx)=y(1+x)^{-1}

\frac{d y}{d x} = y (1 + x)^{- 1}

y = e^{c_{1}} + e^{c_{1}} x

Solution steps

\frac{d y}{d x} = y (1 + x)^{- 1}

Solve separable ODE:

y = e^{c_{1}} + e^{c_{1}} x

y = e^{c_{1}} + e^{c_{1}} x

\int \frac{1}{( x + 3 ) ( x + 5 )} d x

\frac{\partial}{\partial x} ((5 x - x^{2}) cos (t))

Y (s) = \frac{s - 2}{s ^{2} - 2 s - 3}

f (x) = - 3 x^{2} + x + 2, at x = 1

\frac{\partial}{\partial x} (\frac{p}{1 + e ^{c o s (x)}})

What is the solution for (dy)/(dx)=y(1+x)^{-1} ?
The solution for (dy)/(dx)=y(1+x)^{-1} is y=e^{c_{1}}+e^{c_{1}}x