What is the derivative of e^{ax+b} ?

The derivative of e^{ax+b} is e^{ax+b}a

What is the first derivative of e^{ax+b} ?

The first derivative of e^{ax+b} is e^{ax+b}a

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derivative of

e^{a x + b}

e^{a x + b} a

Solution steps

\frac{d}{d x} (e^{a x + b})

Apply the chain rule:

e^{a x + b} \frac{d}{d x} (a x + b)

= e^{a x + b} \frac{d}{d x} (a x + b)

\frac{d}{d x} (a x + b) = a

= e^{a x + b} a

\int sec^{2} (2 x) tan^{5} (2 x) d x

y = 4 x^{2} + 3 x

1 - x^{2}, x^{2} - 3, x + 3

\frac{\partial}{\partial x} (2 (ln (x)) + y)

\frac{\partial}{\partial x} (x (x - 2))

What is the derivative of e^{ax+b} ?
The derivative of e^{ax+b} is e^{ax+b}a
What is the first derivative of e^{ax+b} ?
The first derivative of e^{ax+b} is e^{ax+b}a