What is the derivative of y= 8/x ?

The derivative of y= 8/x is -8/(x^2)

What is the first derivative of y= 8/x ?

The first derivative of y= 8/x is -8/(x^2)

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derivative of

y = \frac{8}{x}

- \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 1 \cdot x^{- 1 - 1})

Simplify

8 (- 1 \cdot x^{- 1 - 1}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

x \to 0 lim (2 x^{2} ln (x))

\frac{d}{d x} (5 \frac{5 x}{4 x - 3})

x \to 0 lim ([x] \cdot sin (\frac{1}{x}))

\int \frac{7 x ^{2} + 8 x - 2}{x ^{2} + 2 x} d x

z \to (2 i) lim (z^{2} - z)

What is the derivative of y= 8/x ?
The derivative of y= 8/x is -8/(x^2)
What is the first derivative of y= 8/x ?
The first derivative of y= 8/x is -8/(x^2)