What is the integral of (2x^2-x-7) ?

The integral of (2x^2-x-7) is (2x^3)/3-(x^2)/2-7x+C

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integral of (2x^2-x-7)

\int (2 x^{2} - x - 7) d x

\frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} - 7 x + C

Solution steps

\int 2 x^{2} - x - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int x d x - \int 7 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 7 d x = 7 x

= \frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} - 7 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} - 7 x + C

\frac{\partial}{\partial x} (ln (3 x + 6 y + 9 z))

\frac{d y}{d x} = x e^{x + y}

\frac{7 x ^{2} + 1}{x ^{2} + 5}

\frac{d}{d x} (7 cot (x))

x \to \infty lim (\frac{4}{x ^{2}})

What is the integral of (2x^2-x-7) ?
The integral of (2x^2-x-7) is (2x^3)/3-(x^2)/2-7x+C