What is the solution for xdx+sin^2(x^{-1}y)(ydx-xdy)=0 ?

The solution for xdx+sin^2(x^{-1}y)(ydx-xdy)=0 is y=-\W(-1/(c_{1)x})x

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xdx+sin^2(x^{-1}y)(ydx-xdy)=0

x d x + sin^{2} (x^{- 1} y) (y d x - x d y) = 0

y = - W (- \frac{1}{c _{1} x}) x

Solution steps

x d x + sin^{2} (x^{- 1} y) (y d x - x d y) = 0

Solve using substitution:

y = - W (- \frac{1}{c _{1} x}) x

y = - W (- \frac{1}{c _{1} x}) x

- \frac{3}{2} x^{2} + 5 x + 5

tan (2 x - x^{3})

\frac{\partial}{\partial x} (x^{3} y + 2 x y^{3})

\int (x + 2) e^{(x + 2)} d x

x \to 5 lim (\frac{x ^{2} + 1}{x + 1})

What is the solution for xdx+sin^2(x^{-1}y)(ydx-xdy)=0 ?
The solution for xdx+sin^2(x^{-1}y)(ydx-xdy)=0 is y=-\W(-1/(c_{1)x})x