What is the limit as x approaches 5 of (x^2+1)/(x+1) ?

The limit as x approaches 5 of (x^2+1)/(x+1) is 13/3

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limit as x approaches 5 of (x^2+1)/(x+1)

x \to 5 lim (\frac{x ^{2} + 1}{x + 1})

\frac{13}{3}

Decimal

4.33333 \dots

Solution steps

x \to 5 lim (\frac{x ^{2} + 1}{x + 1})

Plug in the value

x = 5

= \frac{5 ^{2} + 1}{5 + 1}

Simplify

\frac{5 ^{2} + 1}{5 + 1} : \frac{13}{3}

= \frac{13}{3}

\int \frac{x}{36 x ^{2} + 9} d x

x \to 0 + lim ((1 + 3 x)^{\frac{1}{x}})

\frac{\partial}{\partial x} (- y - \frac{2 x}{y ^{3}})

\int \frac{ln ( x + 1 )}{( x + 1 )} d x

\frac{\partial}{\partial x} (x ln (x + 2 y))

What is the limit as x approaches 5 of (x^2+1)/(x+1) ?
The limit as x approaches 5 of (x^2+1)/(x+1) is 13/3