What is the integral of sin^3(x)cos^{10}(x) ?

The integral of sin^3(x)cos^{10}(x) is -(cos^{11}(x))/(11)+(cos^{13}(x))/(13)+C

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integral of sin^3(x)cos^{10}(x)

\int sin^{3} (x) cos^{10} (x) d x

- \frac{cos ^{11} ( x )}{11} + \frac{cos ^{13} ( x )}{13} + C

Solution steps

\int sin^{3} (x) cos^{10} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x)) sin (x) cos^{10} (x) d x

Apply u-substitution

: \int - u^{10} (1 - u^{2}) d u

= \int - u^{10} (1 - u^{2}) d u

Expand

- u^{10} (1 - u^{2}) : - u^{10} + u^{12}

= \int - u^{10} + u^{12} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int u^{10} d u + \int u^{12} d u

\int u^{10} d u = \frac{u ^{11}}{11}

\int u^{12} d u = \frac{u ^{13}}{13}

= - \frac{u ^{11}}{11} + \frac{u ^{13}}{13}

Substitute back

u = cos (x)

= - \frac{cos ^{11} ( x )}{11} + \frac{cos ^{13} ( x )}{13}

Add a constant to the solution

= - \frac{cos ^{11} ( x )}{11} + \frac{cos ^{13} ( x )}{13} + C

\frac{d}{d x} (\frac{2}{5} x^{\frac{5}{2}})

\int (x^{3} - 2 x^{\frac{1}{2}} + 4)^{2} d x

\frac{d}{d x} (\frac{1}{y - 5 x ^{2}})

y^{^{'}} - y = 2 t

x^{2} y^{^{'}} + 2 x y = 25 cos^{2} (x)

What is the integral of sin^3(x)cos^{10}(x) ?
The integral of sin^3(x)cos^{10}(x) is -(cos^{11}(x))/(11)+(cos^{13}(x))/(13)+C