What is the derivative of 7(4^x) ?

The derivative of 7(4^x) is 7ln(2)*2^{2x+1}

What is the first derivative of 7(4^x) ?

The first derivative of 7(4^x) is 7ln(2)*2^{2x+1}

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derivative of

7 (4^{x})

7 ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (7 \cdot 4^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 7 \cdot 4^{x} ln (4)

Simplify

7 \cdot 4^{x} ln (4) : 7 ln (2) \cdot 2^{2 x + 1}

= 7 ln (2) \cdot 2^{2 x + 1}

x \to - 5 - lim (\frac{1}{x ^{2} - 25})

\frac{d}{d t} (\frac{5 t}{1 + 2 t ^{2}})

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}, y (0) = 0

\int cos (5 x) cos (10 x) d x

\frac{e ^{- s}}{( ( s - 3 ) ( s + 1 ) )}

What is the derivative of 7(4^x) ?
The derivative of 7(4^x) is 7ln(2)*2^{2x+1}
What is the first derivative of 7(4^x) ?
The first derivative of 7(4^x) is 7ln(2)*2^{2x+1}