What is the solution for (dy)/(dt)= 1/((y+1)(t-2)),y(0)=0 ?

The solution for (dy)/(dt)= 1/((y+1)(t-2)),y(0)=0 is y=-1+sqrt(2ln(-t/2+1)+1)

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(dy)/(dt)= 1/((y+1)(t-2)),y(0)=0

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}, y (0) = 0

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

Solution steps

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}

Solve linear ODE:

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

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\frac{e ^{- s}}{( ( s - 3 ) ( s + 1 ) )}

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What is the solution for (dy)/(dt)= 1/((y+1)(t-2)),y(0)=0 ?
The solution for (dy)/(dt)= 1/((y+1)(t-2)),y(0)=0 is y=-1+sqrt(2ln(-t/2+1)+1)