What is the integral of ((ln(x))^{24})/x ?

The integral of ((ln(x))^{24})/x is (ln^{25}(x))/(25)+C

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integral of ((ln(x))^{24})/x

\int \frac{( ln ( x ) ) ^{24}}{x} d x

\frac{ln ^{25} ( x )}{25} + C

Solution steps

\int \frac{( ln ( x ) ) ^{24}}{x} d x

Apply u-substitution

: \int u^{24} d u

= \int u^{24} d u

Apply the Power Rule

: \frac{u ^{25}}{25}

= \frac{u ^{25}}{25}

Substitute back

u = ln (x)

= \frac{ln ^{25} ( x )}{25}

Add a constant to the solution

= \frac{ln ^{25} ( x )}{25} + C

f (x) = ln (x^{l n (x)})

\int_{- \infty}^{- 1} e^{- 20 t} d t

3 t^{2}

\int x^{2} ln (d) x d x

\frac{d}{d x} (x \cdot e^{- s i n (x)} - x)

What is the integral of ((ln(x))^{24})/x ?
The integral of ((ln(x))^{24})/x is (ln^{25}(x))/(25)+C