What is the derivative of \sqrt[3]{t^2} ?

The derivative of \sqrt[3]{t^2} is (2t)/(3(t^2)^{2/3)}

What is the first derivative of \sqrt[3]{t^2} ?

The first derivative of \sqrt[3]{t^2} is (2t)/(3(t^2)^{2/3)}

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derivative of

3 t^{2}

\frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}}

Solution steps

\frac{d}{d t} (3 t^{2})

Apply the chain rule:

\frac{1}{3 ( t ^{2} ) ^{\frac{2}{3}}} \frac{d}{d t} (t^{2})

= \frac{1}{3 ( t ^{2} ) ^{\frac{2}{3}}} \frac{d}{d t} (t^{2})

\frac{d}{d t} (t^{2}) = 2 t

= \frac{1}{3 ( t ^{2} ) ^{\frac{2}{3}}} \cdot 2 t

Simplify

\frac{1}{3 ( t ^{2} ) ^{\frac{2}{3}}} \cdot 2 t : \frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}}

= \frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}}

\int x^{2} ln (d) x d x

\frac{d}{d x} (x \cdot e^{- s i n (x)} - x)

\frac{d}{d x} (\frac{x ^{2} - 3}{x - 2})

\frac{2 x}{1 - tan ( x )}

x y^{^{'}} + y = x^{2} - 2 x + 1

What is the derivative of \sqrt[3]{t^2} ?
The derivative of \sqrt[3]{t^2} is (2t)/(3(t^2)^{2/3)}
What is the first derivative of \sqrt[3]{t^2} ?
The first derivative of \sqrt[3]{t^2} is (2t)/(3(t^2)^{2/3)}