What is the sum from n=0 to infinity of 5/(3^n) ?

The sum from n=0 to infinity of 5/(3^n) is 15/2

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sum from n=0 to infinity of 5/(3^n)

n = 0 \sum \infty \frac{5}{3 ^{n}}

\frac{15}{2}

Solution steps

n = 0 \sum \infty \frac{5}{3 ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty \frac{1}{3 ^{n}}

Apply Series Geometric Test:

\frac{3}{2}

= 5 \cdot \frac{3}{2}

Simplify

5 \cdot \frac{3}{2} : \frac{15}{2}

= \frac{15}{2}

x \to 2 lim (\frac{2 x ^{2}}{x})

\int y (a - b y^{2}) d y

\int x^{2} x - 1 d x

y = arcsin (\frac{3}{x ^{2}})

\frac{d}{d t} (sin^{3} (t))

What is the sum from n=0 to infinity of 5/(3^n) ?
The sum from n=0 to infinity of 5/(3^n) is 15/2