What is inverse oflaplace 2/((s-2)) ?

The answer to inverse oflaplace 2/((s-2)) is 2e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 2/((s-2))

inverse laplace

\frac{2}{( s - 2 )}

2 e^{2 t}

Solution steps

L^{- 1} {\frac{2}{( s - 2 )}}

= L^{- 1} {2 \cdot \frac{1}{s - 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{1}{s - 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 2}} = e^{2 t}

= 2 e^{2 t}

\int x (4 x + 1)^{2} d x

n = 1 \sum \infty (- 1)^{n} \frac{2 n !}{2 ^{n} n ! n}

f (x) = (x^{2} + 1) \cdot e^{x - 1}

\int x^{2} x + 2 d x

\frac{d}{d x} (\frac{14 x + 4 x ^{2}}{( 7 + 4 x ) ^{2}})

What is inverse oflaplace 2/((s-2)) ?
The answer to inverse oflaplace 2/((s-2)) is 2e^{2t}